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JEE MainMathematics
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Limits, Continuity and Differentiability: Mathematics | JEE Main

Let g:RRg: R \rightarrow R be a non constant twice differentiable such that g(12)=g(32)g^{\prime}\left(\frac{1}{2}\right)=g^{\prime}\left(\frac{3}{2}\right). If a real valued function f\mathrm{f} is defined as f(x)=12[ g(x)+g(2x)]\mathrm{f}(\mathrm{x})=\frac{1}{2}[\mathrm{~g}(\mathrm{x})+\mathrm{g}(2-\mathrm{x})], then
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Single correct
Exam relevance
JEE Main · Mathematics
Concepts assessed
Mathematics
Academic status
Reviewed by official_key
Source
pyq
Editorial review
8 September 2026

Students also ask

Why did we evaluate f(x)f'(x) at x=1x = 1?

Because the function has symmetry about x=1x=1, so 21=12-1 = 1, making g(1)g(1)=0g'(1) - g'(1) = 0 automatically vanish, providing a third zero of f(x)f'(x).