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JEE MainMathematics
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Sets, Relations and Functions: Mathematics | JEE Main

For some a,b,cNa, b, c \in \mathbb{N}, let f(x)=ax3f(x) = ax - 3 and g(x)=xb+c,xRg(x) = x^b + c, x \in \mathbb{R}. If (fg)1(x)=(x72)1/3(f \circ g)^{-1}(x) = \left(\frac{x-7}{2}\right)^{1/3}, then (fg)(ac)+(gf)(b)(f \circ g)(ac) + (g \circ f)(b) is equal to
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Source and academic review
Question type
Numerical
Exam relevance
JEE Main · Mathematics
Concepts assessed
Mathematics
Academic status
Reviewed by official_key
Source
pyq
Editorial review
9 September 2026

Students also ask

How do we find f(g(x))f(g(x)) from its inverse function?

If h1(x)=yh^{-1}(x) = y, then h(y)=xh(y) = x. Replacing yy with xx after solving gives the original function h(x)=(fg)(x)h(x) = (f \circ g)(x).

Can we directly compare coefficients of axba x^b and 2x32 x^3?

Yes, because the equality axb+ac3=2x3+7a x^b + ac - 3 = 2x^3 + 7 must hold for all xRx \in \mathbb{R} and a,b,ca, b, c are natural numbers.