StepWorking
01given
a,b,c∈N, f(x)=ax−3, g(x)=xb+c, and (f∘g)−1(x)=(2x−7)1/3.
02goal
Find the value of (f∘g)(ac)+(g∘f)(b).
03approach
Invert (f∘g)−1(x) to find the explicit formula for (f∘g)(x). Then equate it to f(g(x))=a(xb+c)−3 to determine the natural numbers a,b,c. Finally, evaluate (f∘g)(ac) and (g∘f)(b) and compute their sum.
04execute
Let y=(f∘g)−1(x)=(2x−7)1/3. Inverting gives y3=2x−7⟹x=2y3+7. Hence, (f∘g)(x)=2x3+7.
05execute
Compute f(g(x)) from definitions: f(g(x))=a(xb+c)−3=axb+ac−3. Equating this to 2x3+7 for all x: axb+(ac−3)=2x3+7. By comparing coefficients and exponents: a=2, b=3, and ac−3=7⟹2c=10⟹c=5. Since a,b,c∈N, these values are valid. Then ac=2×5=10.
06execute
Calculate the two terms: First, (f∘g)(ac)=(f∘g)(10)=2(10)3+7=2(1000)+7=2007. Second, evaluate (g∘f)(b)=g(f(3)). Since f(3)=a(3)−3=2(3)−3=3, we have g(f(3))=g(3)=3b+c=33+5=27+5=32.
07execute
Sum the two values: (f∘g)(ac)+(g∘f)(b)=2007+32=2039.
✓verify
Check: f(x)=2x−3, g(x)=x3+5. (f∘g)(x)=2(x3+5)−3=2x3+7. Its inverse is y=2x3+7⟹x=(2y−7)1/3, which matches the stem exactly.