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JEE Main · Physics · Laws of Motion
Required friction vs limiting friction
A 2 kg block remains at rest on a rough horizontal surface. The coefficient of static friction is 0.5 and g = 10 m/s². A horizontal force of 6 N is applied. What is the static friction force?
You chose · Correct: B · 6 N opposite to the applied force
A 2 kg block remains at rest on a rough horizontal surface. The coefficient of static friction is 0.5 and g = 10 m/s². A horizontal force of 6 N is applied. What is the static friction force?
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Hint 1 of 4
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The block remains at rest. What must be true horizontally?
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Balance
The block is at rest, so the net horizontal force must be zero.
Direction
The applied force tends to move the block right, so static friction acts left.
Required
For equilibrium, f required = 6 N.
Available
f maximum = μₛN = 0.5 × 2 × 10 = 10 N.
Answer
6 N is within the 10 N limit, so f = 6 N opposite to the applied force.
Transfer check
+4 marksSame decision. New numbers.
The applied force becomes 8 N while the maximum static friction remains 10 N. What friction acts on the block?
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